The Acceleration of a Fighter Jet Catapulted Off an Aircraft Carrier

A fighter jet is catapulted off an aircraft carrier from rest to 75 m/s. If the aircraft carrier deck is 100 m long, what is the acceleration of the jet?

The acceleration of the jet is 28.1 m/s2.

Explanation:

Since the motion of the jet is a uniformly accelerated motion, we can use the following suvat equation:

v2-u2=2as

where:

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the jet in this problem, we have:

u = 0

v = 75 m/s

s = 100 m

Solving for a, we find the acceleration:

a = (v2-u2)/(2s) = (752-0)/(2*100) = 28.1 m/s2

Final answer:

The acceleration of the jet as it is catapulted off the aircraft carrier is found to be approximately 28.125 m/s2, utilizing the third equation of motion.

Explanation:

This question pertains to one-dimensional motion, where the jet travels a known distance at a constant speed from a state of rest. Here, you apply the third equation of motion: final velocity2 = initial velocity2 + 2 * acceleration * distance. The initial velocity in this case is 0 m/s because the jet was at rest, the final velocity is 75 m/s, and the distance is 100 m. Substituting these values into the equation gives: (75 m/s)2 = (0 m/s)2 + 2 * acceleration * 100 m. Solving for acceleration, it comes out to be approximately 28.125 m/s2.

A fighter jet is catapulted off an aircraft carrier from rest to 75 m/s. If the aircraft carrier deck is 100 m long, what is the acceleration of the jet?

The acceleration of the jet is 28.1 m/s^2.

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