Free Fall Velocity Calculation

What is the velocity of an object falling freely from rest and reaching the ground in 2 seconds, given an acceleration due to gravity of 9.8 m/s²? The velocity of the object upon reaching the ground after 2 seconds is 19.6 m/s.

Final answer: Applying the physics formula v = u + at to the scenario of an object falling freely from rest under the acceleration of gravity, the final velocity of the object upon reaching the ground after 2 seconds is found to be 19.6 m/s.

Explanation:

In Physics, the velocity of an object under acceleration is given by the formula v = u + at, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration, and 't' is the time. In this scenario, an object is falling freely from rest, meaning it has an initial velocity (u) of 0 m/s. The object is reaching the ground in 2 seconds, so 't' is 2s. The acceleration 'a' is due to gravity, which is 9.8 m/s².

Substituting these values into the above formula, we have: v = 0 + (9.8 * 2).

Therefore, the velocity of the object on reaching the ground will be 19.6 m/s. So, the correct answer is D) 19.6 m/s.

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