Force Required to Keep the Top Plate Moving at 18 m/s
What is the force required to keep the top plate moving at 18 m/s if it has an area of 2 m2?
Given the viscosity of water is 0.89 centipoise and the distance between the plates is 1 cm.
Answer:
The force required to keep the top plate moving at a velocity of 18 m/s is 3.204 N.
To calculate the force required to keep the top plate moving at a constant velocity, we use the equation:
F = (nAv) / L
Where:
F is the force,
n is the coefficient of viscosity (0.89 centipoise),
A is the area of the plate (2 m2),
v is the velocity (18 m/s), and
L is the distance between the plates (1 cm).
Substitute the given values into the equation:
F = (0.89 centipoise * 2 m2 * 18 m/s) / 1 cm
Converting units and simplifying:
F = (0.89 * 10^(-2) Ns/m2 * 2 m2 * 18 m/s) / (1 * 10^(-2) m)
Therefore, the force required to keep the top plate moving at a velocity of 18 m/s is 3.204 N.