You kick a soccer ball with an initial vertical velocity of 14 m/s and a horizontal velocity of 18 m/s. What is the initial resultant velocity of the soccer ball?
Answer:
Explanation:
When we have the initial vertical velocity and horizontal velocity of a soccer ball, we can calculate the initial resultant velocity using Pythagoras' theorem.
The formula for Pythagoras' theorem is V = √((vertical velocity)^2 + (horizontal velocity)^2).
Given:
Initial vertical velocity (u) = 14 m/s
Horizontal velocity (v) = 18 m/s
Using the formula:
V = √((14^2) + (18^2))
V = √(196 + 324)
V = √520
V ≈ 22.8 m/s
Final answer:
The initial resultant velocity of the soccer ball is approximately 22.8 m/s.
Explanation:
The initial resultant velocity of a soccer ball can be calculated using Pythagoras' theorem as we are given the two component velocities. This theorem is used because the motion is in two dimensions - i.e., horizontal and vertical. The initial vertical velocity is 14 m/s and the horizontal velocity is 18 m/s. Therefore, using Pythagoras' theorem, the initial resultant velocity (V) would be the square root of the sum of the squares of these two values.
V = √((14^2) + (18^2))
V = √(196 + 324)
V = √520
Therefore, the initial resultant velocity of the soccer ball is approximately 22.8 m/s.
What formula is used to calculate the initial resultant velocity of a soccer ball when given the vertical and horizontal velocities?
The formula used to calculate the initial resultant velocity of a soccer ball when given the vertical and horizontal velocities is V = √((vertical velocity)^2 + (horizontal velocity)^2), based on Pythagoras' theorem.