Iron Production Calculation - Let's Crunch the Numbers!

What was the actual yield of iron in moles?

actual yield: mol

What is the theoretical yield of iron in moles?

theoretical yield:

What was the percent yield?

percent yield:

Answer:

The actual yield of iron in moles was 0.279 mol. The theoretical yield of iron was 0.438 mol. The percent yield was 63.7%.

Iron is a crucial element in many industrial processes, and calculating its production yield is essential for efficiency. In this particular scenario, we were given the information that 0.219 mol of Fe,0, reacted with excess carbon to produce an actual yield of 15.6g of Fe. By using stoichiometry and the given balanced chemical equation, we were able to determine the actual yield of iron in moles.

To calculate the actual yield of iron in moles, we utilized the mass of iron obtained in grams and the molar mass of iron. By converting the mass of iron to moles, we found that the actual yield was 0.279 mol.

Next, we determined the theoretical yield of iron in moles by considering the stoichiometry of the reaction. From the balanced equation, we established the molar ratio between Fe,0, and Fe, which allowed us to calculate the theoretical yield as 0.438 mol.

Finally, to find the percent yield, we compared the actual yield to the theoretical yield using the formula: Percent yield = (actual yield / theoretical yield) x 100. By plugging in the values, we obtained a percent yield of 63.7%.