Volume Calculation in Acid-Base Neutralization Reaction

Calculating the Volume of Potassium Hydroxide Solution Needed

When calculating the volume of a solution needed to neutralize another solution in an acid-base reaction, we can use the formula: (Ca x Va)/(Cb x Vb) = Na/Nb

Given Data:

Volume of KOH Vb = ?

Concentration of KOH Cb = 0.149 M

Volume of HBr Va = 17.0 ml

Concentration of HBr Ca = 0.112 M

Equation:

HBr(aq) + KOH(aq) → KBr(aq) + H2O(l)

Mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; Nb, number of moles of KOH is 1)

Solution:

(Ca x Va)/(Cb x Vb) = Na/Nb

(0.112 x 17.0)/(0.149 x Vb) = 1/1

1.904 = 0.149Vb

Vb = 1.904/0.149

Vb = 12.78 ml

Therefore, 12.78 ml of potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 M hydrobromic acid solution.

what volume of a 0.149 M potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 M hydrobromic acid solution? Answer: 12.78 ml
← Tantalizing tantalum exploring the element 73 Washing methods in chemistry sodium bicarbonate and sodium bisulfite →