# The Chemistry Questions You Need Answered!

## Question 1:

What is the mass of NaHCO3 required to produce 224L of CO2 at STP?

## Answer:

The mass of NaHCO3 required to produce 224L of CO2 at STP is 840 grams.

## Explanation:

**To calculate the mass of NaHCO3 required to produce 224L of CO2 at STP, we can use the stoichiometry of the balanced equation and the molar volume of gases at STP.** From the balanced equation, we can see that 1 mole of NaHCO3 produces 1 mole of CO2. Therefore, the number of moles of CO2 produced can be calculated using the molar volume of gases at STP: 1 mole of any gas occupies 22.4 liters at STP.

So, the number of moles of CO2 produced is: 224L CO2 * (1 mole CO2 / 22.4L CO2) = 10 moles CO2. Since the balanced equation tells us that 1 mole of NaHCO3 produces 1 mole of CO2, the number of moles of NaHCO3 required is also 10 moles.

The molar mass of NaHCO3 is 84 g/mol, so the mass of NaHCO3 required is: 10 moles NaHCO3 * 84 g/mol = 840 g NaHCO3.