Interesting Chemistry Problems

Question:

Propane, C3H8, is the fuel in barbecue tanks. Calculate the volume that 4.5 mol of propane occupies at STP.

Answer:

The fertilizer ammonium sulfate, (NH4)2SO4, is prepared by the reaction of ammonia, NH3, with sulfuric acid: 2 NH3 (g) + H2SO4 (aq) → (NH4)2SO4 (aq). How many moles of ammonium sulfate are produced if 1.50 moles of ammonia react completely at STP?

To calculate the volume of 4.5 mol of propane at STP, we first need to determine the molar volume of a gas at STP. The molar volume of gas at STP is approximately 22.4 L/mol. Therefore, the volume occupied by 4.5 mol of propane at STP would be 4.5 mol x 22.4 L/mol = 100.8 L.

For the reaction between ammonia and sulfuric acid, the balanced equation indicates that 2 moles of NH3 react to produce 1 mole of (NH4)2SO4. Therefore, if 1.50 moles of ammonia react completely, the moles of (NH4)2SO4 produced would be 0.750 moles.