How to Calculate Volume of Potassium Iodide Solution?

What is the volume of a 0.998 mol/L potassium iodide solution containing 200.g of KI?

Calculate the volume in liters of a 0.998 mol/L potassium iodide solution that contains 200.g of potassium iodide (KI). Round your answer to 3 significant digits.

Answer:

The volume of the potassium iodide solution is 0.382 L.

To calculate the volume of a potassium iodide solution, we need to follow these steps:

  1. Calculate the molar mass of potassium iodide (KI):
    Molar Mass of KI = Atomic Mass of K + Atomic Mass of Iodine = 39.0983 g/mol + 126.90447 g/mol = 166.00277 g/mol
  2. Determine the number of moles of potassium iodide in the solution:
    Number of Moles of KI = Mass of KI / Molar Mass of KI = 200 g / 166.00277 g/mol = 1.2019 mol
  3. Calculate the volume of the solution:
    Volume of Solution = Number of Moles of KI / Concentration of Solution = 1.2019 mol / 0.998 mol/L = 1.204 L

Therefore, the volume of the potassium iodide solution containing 200.g of KI is 0.382 liters, rounded to 3 significant digits.

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