Gas Law Problem: Pressure and Temperature Relationship

Solving a Gas Law Problem

A gas at 300 K occupies 6.50 L at a pressure of 3.50 atm. What will its pressure be at 250 K if its volume is reduced to 4.80 L?

To solve this problem, we can use the ideal gas law equation:

P1V1 / T1 = P2V2 / T2

First, we need to identify the given values:

• P1 = 3.50 atm (initial pressure)
• V1 = 6.50 L (initial volume)
• T1 = 300 K (initial temperature)
• V2 = 4.80 L (final volume)
• T2 = 250 K (final temperature)

Now, plug in the values into the equation to find the final pressure (P2):

P2 = (P1V1 / T1) * (T2 / V2)

Calculating the values:

P2 = (3.50 atm * 6.50 L / 300 K) * (250 K / 4.80 L) = 2.71 atm

Therefore, the pressure of the gas at 250 K with a volume of 4.80 L will be 2.71 atm.

Make sure to double-check your calculations and show all your work to understand the process clearly.