Determining [H3O+), (OH), POH and pH in a Neutralization Reaction
Understanding the Neutralization Reaction
When 45mL of 0.20M HBr is mixed with 115mL of 0.25M KOH, a neutralization reaction occurs. In this reaction, the H+ ions from the acid (HBr) combine with the OH- ions from the base (KOH) to form water. The remaining ions after neutralization are used to determine the concentration of [H3O+), (OH), POH and pH.
Final Answer
The concentration of [H3O+), (OH), POH and pH can be determined by analyzing the neutralization reaction between HBr and KOH. With equal moles of H+ and OH- ions produced, the concentration of [H3O+] will be equal to that of KOH. Similarly, the concentration of (OH) will be equal to that of HBr. Lastly, the pH can be calculated using the equation pH + pOH = 14.
Explanation
To determine the [H3O+], we can use the concept of neutralization reaction between the acid (HBr) and the base (KOH). Since the mole ratio of HBr to KOH is 1:1, we have equal amounts of H+ and OH- ions produced. Therefore, the concentration of H3O+ will be equal to the concentration of KOH, which is 0.25 M.
To find the concentration of OH-, we can use the same reasoning. The concentration of OH- is equal to the concentration of HBr, which is 0.20 M.
Using the equation pH + pOH = 14, we can calculate the pH and pOH. The pOH is equal to -log[OH-], so pOH = -log(0.20) = 0.70. Therefore, the pH is 14 - 0.70 = 13.30.
Question: How can the concentration of [H3O+), (OH), POH, and pH be determined in a neutralization reaction between HBr and KOH? Answer: The concentration of [H3O+] can be found by comparing it to the concentration of the base KOH. The concentration of (OH) is determined by comparing it to the concentration of the acid HBr. Lastly, the pH can be calculated using the equation pH + pOH = 14.