Complete Reaction of Bases with HCl Solution

How to determine the volume of different bases needed to completely react with a specific amount of HCl solution?

What volume of each of the following bases will react completely with 27.00 mL of 0.550 M HCl?

a) 0.100 M NaOH: 490 mL

b) 0.0500 M Ba(OH)2: 2480 mL

c) 0.250 M KOH: Volume not provided

Calculation of Base Volumes for Complete Reaction

The volume of each base required to completely react with 27.00 mL of 0.550 M HCl can be determined using the stoichiometry concept and balanced chemical equations.

To determine the volume of each base needed for complete reaction with a given volume and concentration of HCl, we can use the balanced chemical equation and the concept of stoichiometry.

The balanced chemical equation for the reaction between an acid (HCl) and a base (NaOH, Ba(OH)2, or KOH) is:

HCl + Base → Salt + Water

From the balanced equation, we can see that the stoichiometric ratio between HCl and the base is 1:1, meaning that one mole of HCl reacts with one mole of the base.

To calculate the volume of each base needed, we can use the formula:

Volume (Base) = (Volume (HCl) * Concentration (HCl)) / Concentration (Base)

Let's calculate the volumes for each base:

0.100 M NaOH:

Volume (NaOH) = (27.00 mL * 0.550 M) / 0.100 M = 490 mL

0.0500 M Ba(OH)2:

Volume (Ba(OH)2) = (27.00 mL * 0.550 M) / 0.0500 M = 2480 mL

0.250 M KOH:

The volume of KOH required is not provided in the given data. Additional information is needed to calculate the volume.