Chemistry Problem-Solving: Finding the Volume of Solution Needed

What volume of a 4.70 M solution of NaNO₃ do you need to make 0.480 L of a 1.70 M solution of NaNO₃? To make a 0.480 L of a 1.70 M solution of NaNO₃ from a 4.70 M solution, you would need a volume of 0.173 L.

Exploring Chemistry Solution-Volume Calculation

When tackling chemistry problems involving finding the volume of solution needed, it's essential to remember the equation M1V1 = M2V2. This formula allows us to calculate the volume of a certain concentration solution needed to create a specific concentration solution.

In this scenario, we are given the following information:

M1 (initial molarity) = 4.70 M

V2 (final volume) = 0.480 L

M2 (final molarity) = 1.70 M

By plugging these values into the formula M1V1 = M2V2 and solving for V1, we can determine the volume of the 4.70 M solution of NaNO₃ needed:

(4.70 M)(V1) = (1.70 M)(0.480 L)

V1 = (1.70 M)(0.480 L) / (4.70 M) = 0.173 L

Therefore, the volume of the 4.70 M solution of NaNO₃ required to create a 0.480 L of 1.70 M solution is 0.173 L. This calculation demonstrates the power of understanding molarity and volume relationships in chemistry problem-solving.

← Organic chemistry nomenclature and stereochemistry What will janie s other hand be doing while slicing an apple for her afternoon snack →

More Posts: