Calculate the Mass of 1.59 Moles of NH3

What is the mass of 1.59 moles of NH3? The mass of 1.59 moles of NH3 can be calculated using the formula moles (n) = mass (m) / Molar mass (M). Given moles = 1.59, we need to find the molar mass of NH3 to calculate the mass. The molar mass of NH3 is found by adding the atomic masses of nitrogen (N) and hydrogen (H) in the molecule.

To find the molar mass of NH3, we add the atomic masses of nitrogen (N) and hydrogen (H).

Molar mass (NH3) = N + 3H

Since the atomic mass of N is 14 and the atomic mass of H is 1, substituting the values gives us: M(NH3) = 14 + 3(1) = 17

Now, we can use the formula moles (n) = mass (m) / Molar mass (M) to find the mass.

Given moles (n) = 1.59 and Molar mass (M) = 17, we can rearrange the formula to solve for mass (m):

m = n * M

Therefore, the mass of 1.59 moles of NH3 is calculated as:

m = 1.59 * 17 = 27.03 grams

So, the mass of 1.59 moles of NH3 is 27.03 grams.

← Equilibrium constant calculation and naturally occurring potassium isotopes Heat capacity calculation in bomb calorimetry experiment →

More Posts: