Calculate the Concentration of Ethanol in Molality

What is the concentration of ethanol in the liquor?

A particular liquor is 49.0% ethanol (CH3CH2OH) by volume. Calculate the concentration of ethanol in molality.

The concentration of ethanol in the liquor is 0.0405 mol/L or 40.5 molality.

The concentration of a substance in a solution can be calculated using the following equation:

C = [solute] * V / V_total

where C is the concentration of the solute in molality, [solute] is the concentration of the solute in moles per liter, V is the volume of the solvent in liters, and V_total is the total volume of the solution in liters.

We are given that the liquor is 49.0% ethanol by volume, which means that it contains 49% ethanol by weight. To convert this to a concentration in molality, we can use the following equation:

[solute] = 0.49 * 0.789 g/mL * 1 L/1000 mL = 0.0405 mol/L

Therefore, the concentration of ethanol in the liquor is 0.0405 mol/L or 40.5 molality.

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