Boyle's Law Calculation: Determining the Pressure of Compressed Gas

What is the final pressure of the gas in the syringe after the volume is reduced from 5.0 mL to 2.1 mL at a pressure of 115 mm Hg?

The final pressure of the gas in the syringe after the volume is reduced from 5.0 mL to 2.1 mL at a pressure of 115 mm Hg is 273.8 mmHg.

Explanation

Data obtained from the question include:
Initial Volume (V1) = 5.0 mL
Initial Pressure (P1) = 115 mmHg
Final Volume (V2) = 2.1 mL
Final Pressure (P2) = ?

Boyle's Law equation states that P1V1 = P2V2. By plugging in the values:
115 x 5 = P2 x 2.1
P2 = (115 x 5) / 2.1
P2 = 273.8 mmHg

Therefore, the final pressure, i.e., the pressure of the compressed gas, is 273.8 mmHg.

What is the new pressure of the gas in atm units after the volume reduction and pressure change in the syringe?

The new pressure of the gas in the syringe is 0.360 atm or 273.8 mmHg.

Explanation

Step 1: Data given
Volume = 5.0 mL = 0.005 L
Initial Pressure = 115 mmHg = 0.151316 atm
Volume reduced to 2.1 mL = 0.0021 L

Step 2: Calculate the new pressure of the gas
Using the Boyle's Law formula: P1V1 = P2V2
P2 = (P1 * V1) / V2
P2 = (0.151316 * 0.005) / 0.0021
P2 = 0.360 atm
OR
P2 = 115 * 0.005 / 0.0021
P2 = 273.8 mmHg

Therefore, the new pressure of the gas is 0.360 atm or 273.8 mmHg.
← Stereoisomer stability understanding the more stable stereoisomer What volume will 3 50 mol of ammonia gas occupy at conditions of standard temperature pressure →

More Posts: