What are the predicted phenotypes and fractions when crossing a parent that is homozygous recessive for both traits with a dihybrid? How can we determine the fur color and eye color of the offspring?
The predicted phenotypes and fractions in the data table would be as follows:
- Black fur and black eyes: 6/16
- Black fur and red eyes: 6/16
- White fur and black eyes: 2/16
- White fur and red eyes: 2/16
Analysis of Offspring Phenotypes
In the Punnett square, the male parent (homozygous recessive) has alleles bb and ee for fur color and eye color, respectively. The female parent (dihybrid) also has alleles bb and ee for fur color and eye color, respectively.
The Punnett square for this cross would look like this:
```
b b
e e
b bb be be
b bb be be
e be be ee
e be be ee
```
Now, let's determine the phenotypes for each offspring in the Punnett square. The fur color is determined by the presence of the dominant allele B, while the eye color is determined by the presence of the dominant allele E.
The predicted phenotypes for the offspring in the Punnett square are as follows:
- 6 offspring will have black fur and black eyes (bbEE)
- 6 offspring will have black fur and red eyes (bbEe)
- 2 offspring will have white fur and black eyes (bbee)
- 2 offspring will have white fur and red eyes (bbee)
Therefore, the predicted fraction of each phenotype is as follows:
- Black fur and black eyes: 6/16
- Black fur and red eyes: 6/16
- White fur and black eyes: 2/16
- White fur and red eyes: 2/16